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Algorithm for adding leading zerosI’ve always been writing this.
function addZero(n:int):String {
if (n < 10) {
return "0" + n;
}else {
return "" + n;
}
}
The function adds one leading 0 quite well but if two 0 is needed, it's quite bad to write all the conditions to check whether it's less than 100 or 10. I think the following code is more efficient.
function addZero(n:int, numZeros:int = 1):String {
var str:String = n + "";
while (str.length<numZeros+1)
{
str = "0" + str;
}
return str;
}
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Hi, I think you have forgot the return statement.
function addZero(n:int, numZeros:int = 1):String {
var str:String = n + “”;
while (str.length<numZeros+1)
{
str = “0″ + str;
}
return str;
}
You arguments should be unsigned int or otherwise you will end up with smth like: “000-10″.
My try would be:
function addZero(n:uint, numZeros:uint):String{
return (new Array(numZeros).join(”0″)) + n;
}
Cheers!
@Fernando, I will blame the programmer whoever tries to pass “-1″ in to add zeros in front of it. It’s pointless to use uint either. It’ll end up as a very big integer.
Anyway, very cool algorithm. Smarter than mine, definitely!
I think that a good solution is this:
function addLeadingZeros(n:Number, q:Number):String
{
return Math.pow(10, q – n.toString().length).toString().substr(1) + n;
}
Without the unnecessary loop.
Cheers
Adding a little bit to @Fernandos post. You need to add 1 to the number of zeros to join to make it come out to the correct number. I also made it so that the number of zeros to add defaults to 1.
public static function addLeadingZero(n:int, numZeros:int = 1):String
{
return (new Array(numZeros + 1).join(’0′)) + n as String;
}